C语言中如何复制数组的内容

#include"string.h"

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#include"stdio.h"

intmain(void)

{

inti,j;

inta[2][3]={{1,2,3},{4,5,6}};

intb[2][3];

memcpy(b[0][0],a[0][0],24);

printf("%d",b[1][0]);

}

扩展资料

#includestdio.h

#includestring.h

#includestdlib.h

voidprintarr2d(int(*a)[3],introw,intcol);

intmain()

{

inti,j;

inta[2][3]={{1,2,3},{4,5,6}};

intb[4][3]={{0,0,0},{0,0,0}};

memcpy(b[2],a,sizeof(int)*2*3);

printarr2d(b,4,3);

return0;

}

/***********************************************

打印显示数组

************************************************/

voidprintarr2d(int(*a)[3],introw,intcol)

{

inti,j;

for(i=0;irow;i++)

{

for(j=0;jcol;j++)

{

printf("%d",a[i][j]);

}

printf("\n");

}

}

c++数组复制的函数

C++ 复制函数

一、场景一：全部默认

#include

class base

{

public:

base()

{

}

base(int dt):

data(dt){

}

void get()

{

printf("base::data = %d\n",data);

}

public:

int data;

};

class derived:public base

{

public:

derived()

{

}

derived(int dt,int ddt):

base(dt),ddata(ddt)

{

}

void get()

{

base::get();

printf("derived::ddata = %d\n",ddata);

}

private:

int ddata;

};

int main()

{

derived da(1,5);

derived db(2,10);

da.get();

db.get();

da = db;

da.get();

db.get();

derived dc(da);

dc.get();

base ba(da);

ba.get();

getchar();

}

场景二、基类默认，派生类自定义

#include

class base

{

public:

base()

{

}

base(int dt):

data(dt)

{

}

void get()

{

printf("base::data = %d\n",data);

}

public:

int data;

};

class derived:

public base

{

public:

derived()

{

}

derived(int dt,int ddt)

:base(dt),ddata(ddt)

{

}

derived(const derivedd)

{

printf("call derived::copy construct function.\n");

ddata = d.ddata;

}

derived operator=(const derivedd)

{

printf("call derived::operator= function.\n");

ddata = d.ddata;

return *this;

}

void get()

{

base::get();

printf("derived::ddata = %d\n",ddata);

}

private:

int ddata;

};

场景三、基类自定义，派生类默认

#include

class base

{

public:

base()

{

}

base(int dt):

data(dt)

{

}

base(const baseb)

{

printf("call base::copy construct function.\n");

data = b.data;

}

base operator=(const based)

{

printf("call base::operator= function.\n");

data = d.data;

return *this;

}

void get()

{

printf("base::data = %d\n",data);

}

public:

int data;

};

class derived:public base

{

public:

derived()

{

}

derived(int dt,int ddt):

base(dt),ddata(ddt)

{

}

void get()

{

base::get();

printf("derived::ddata = %d\n",ddata);

}

private:

int ddata;

};

场景四、基类派生类都自定义

#include

class base

{

public:

base()

{

}

base(int dt):

data(dt)

{

}

base(const baseb)

{

printf("call base::copy construct function.\n");

data = b.data;

}

base operator=(const based)

{

printf("call base::operator= function.\n");

data = d.data;

return *this;

}

void get()

{

printf("base::data = %d\n",data);

}

public:

int data;

};

class derived:public base

{

public:

derived()

{

}

derived(int dt,int ddt):

base(dt),

ddata(ddt)

{

}

derived(const derivedd):base(d)

{

printf("call derived::copy construct function.\n");

ddata = d.ddata;

}

derived operator=(const derivedd)

{

printf("call derived::operator= function.\n");

ddata = d.ddata;

return *this;

}

void get()

{

base::get();

printf("derived::ddata = %d\n",ddata);

}

private:

int ddata;

};

c语言 复制数组

strcpy(t[i],a[j],n);该语句的意思是：将某已知二维数组a的第j行前n个字符复制到另一个二维数组t的第i行中。给分吧

C语言必做复制函数数组

#include stdio.h

#includestring.h

int main()

{

char ch[40];

char c[20]={"asdfgh"};

strcpy(ch,c);

printf("%s\n",ch);

}

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