用C语言编写一个计算自己年龄的函数。

struct Date{

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int year;

int month;

int day;

};

Date * fun(Date *date){

Date today;

today.year = 2013;

today.month = 7;

today.day = 1;

Date age;

age.year = today.year - date-year;

age.month = today.month - date-month;

age.day = today.day - date-day;

return age;

}

int main(){

Date me;

me.year = 1980;

me.month = 6;

me.day = 12;

Date * age = fun(me);

printf("%d%d%d",age-year,age-month,age-day);

return 0;

}

如何用C语言编写输入出生年月，求出年龄的代码

#includestadio.h

main()

{ int year,year1,month,month1,day,day1,age;

printf("请输入您的生日:");

scanf("%d %d %d",year,month,day);

printf("请输入当前日期:");

scanf("%d %d %d",year1,month1,day1);

if(year1==year)

age=0;

else

{age=year1-year;

if(month1month||(month1==monthday1day))

age=age-1;

}

printf("您的年龄是:%d",age);

}

计算年龄的C语言程序

#include

stdio.h

void

main()

{

int

y1,m1,d1,y0,m0,d0,y,m,d;

printf("请输入当前日期\n");

printf("y1=");

scanf("%d",y1);

printf("m1=");

scanf("%d",m1);

printf("d1=");

scanf("%d",d1);

printf("请输入学生的生日\n");

printf("y0=");

scanf("%d",y0);

printf("m0=");

scanf("%d",m0);

printf("d0=");

scanf("%d",d0);

y=y1-y0;

m=m1-m0;

d=d1-d0;

printf("该学生的年龄为%d

%d

%d",y,m,d);

}

已经成功运行

祝你学业有成

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